Color mixer

[WojTec]

Hi, thanks!

Float point version working, but: first element in result is first input color, then steps-1 are real steps. Why?

Second int version is making black-white gradient, why?

[Iwo Asnet]

There is a small error in the float-version: If you want 3 steps, you need a delta of 0.5 (0->0.5->1.0), so Delta should be 1/(Steps-1);

Delphi-Quellcode:

Delta := 1/ (Steps-1);
MixRatio := 0;
For i:=0 To Steps-1 do begin
  ColorArray[i] := MixColors(Color1, color2, MixRatio);
  MixRatio := MixRatio + Delta
End;

For question #2 I leave it up to you to find the error yourself (I found it in 5 secs).

[WojTec]

Thanks, I tried it too, but I forgot about ( and )

And what about BW gradient from int version?

[Furtbichler]

Zitat von WojTec:

And what about BW gradient from int version?

I also...

Zitat:

leave it up to you to find the error yourself.

Hint: It's a copy & paste error in the Blend-Function

[WojTec]

Guys, how to do something similar, but with color wheel, mean not only 2 colors gradient, but N colors beetwen 2 input colors?

[Furtbichler]

Are you lazy? Blend Color1->Color2, then Color2->Color3 etc.

[WojTec]

I don't understand you, what I need to blend with?

[Medium]

He means that you simply need to string pairwise blended colors together. That's the common way of doing it, and most probably also the by far easiest, especially if you have gradients for two colors already implemented (since it's the same thing, just done a few times in a row).

[WojTec]

When I'll blend red and magenta (above image) I'll get RGB(255, 0, 127), this color isn't in example output. So, I still don't understand what I need to blend?

[Medium]

Ah! You don't want to blend with multiple preset colors in between, but using a different color model I suppose! The above looks like the blending was done in HSV or HSL space. (Don't know if right- or left-handed hue, but that should be simple enough to try out.) So instead of blending using RGB, just do it in HSV/HSL. That should get you pretty close to the above result.