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neumimnemecky

Registriert seit: 21. Dez 2018
45 Beiträge
 
#1

einen Datensatzmitgliedsnamen dynamisch zuweisen

  Alt 6. Jul 2022, 10:58
(to assign a record member name dynamically)

Guten Tag,
Ich suche Hilfe, um diesen Code zu vereinfachen und die aus der INI-Datei gelesenen Werte einer Variablen vom Typ "Datensatz" zuzuweisen, wobei sich der Elementname vom Schlüsselnamen in der INI-Datei unterscheidet. Ich habe nicht herausgefunden, wie ich den Mitgliedsnamen dynamisch zuweisen kann, da es zwei Gruppen (A und B) mit denselben Schlüsselnamen in der Datei, aber unterschiedlichen Namen im Datensatz gibt.

Code:
// ini file contains pairs key_name=value , the record contains abbreviated key name
if pars[0] = 'first_frame' then k := 'first_'+group else
  if pars[0] = 'end_frame' then k := 'last_'+group else
    if pars[0] = 'first_filename' then k := 'start_name_'+group else
       if pars[0] = 'path' then
         k := 'path_'+group else
           if pars[0] = 'check_if_files_exist' then
             k := 'check_files_exist_'+group;

if group = 'A' then
 begin
   if k = 'path_A' then
     ini.basic.path_A := pars[1] else
   if k = 'first_A' then
     ini.basic.first_A := pars[1] else
   if k = 'last_A' then
     ini.basic.last_A := pars[1] else
   if k = 'start_name_A' then
     ini.basic.start_name_A := pars[1] else
   if k = 'check_files_exist_A' then
     ini.basic.check_files_exist_A := true;
 end
else if group = 'B' then
 begin
   if k = 'path_B' then
     ini.basic.path_B := pars[1] else
   if k = 'first_B' then
     ini.basic.first_B := pars[1] else
   if k = 'last_B' then
     ini.basic.last_B := pars[1] else
   if k = 'start_name_B' then
     ini.basic.start_name_B := pars[1] else
   if k = 'check_files_exist_B' then
     ini.basic.check_files_exist_B := true;
 end;
end;
(English: Good morning,
I'm looking for help to simplify this code, assigning the values read from ini file to a variable of type Record, where the member name is different from the name of the key in the ini file. I haven't figured out how can I assign the member name dynamically because there are two groups (A and B) with the same key names in the file but different names in the record.)

Deklaration:
Code:
type TBasicSettings = record
  is_scroll_vertical: boolean; scroll_type=vertical
  is_image_direction_up: boolean;
  is_search_colors_HSL: boolean;
  path_A: string;
  path_B: string;
  check_files_exist_A: boolean;
  check_files_exist_B: boolean;
  RAM_disk: string;
  RAM_free: LongWord;
  start_name_A: string;first_filename
  first_A: string;first_frame
  last_A: string;end_frame=
  start_name_B: string;first_filename
  first_B: string;first_frame
  last_B: string;end_frame
  fps: byte;
  scroll_max_shift: integer;
end;
basic.ini
[GENERAL]
Code:
[GENERAL]
scroll_type=vertical
image_direction=up
search_colors_in=HSL
H_max_difference_deg=10%
S_max_difference_per=20%
L_max_difference_per=10%
;V_max_difference_per=10%
padding_left=22
padding_right=25
padding_top=0
padding_bottom=0
detect_max_character_count_on_screen=3
arrow_1_count=2
arrow_2_count=1
arrow_3_count=1
image_1_count=1
skip_detections_on_screen_when_frame_position_is_determined=1
group_to_copy_image_data_from=A
text_copy_color_direction=BA
RAM_disk=A:
RAM_disk_free_space=1GB

Geändert von neumimnemecky ( 6. Jul 2022 um 14:08 Uhr)
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